Question

please answer question no. 13

Answer 1

since
x=2 + 2⅔ + 2⅓,

then

x-2=2⅔ + 2⅓,

now cubing both sides, we have

(x-2)³=(2⅔ + 2⅓)³,

x³-8-3×x×2(x-2)=4+2+3×2⅔×2⅓(2⅔+2⅓),

x³-8-6x²+12x=6+3×2(x-2),

x³-8-6x²+12x=6+6x-12,

then
x³-8-6x²+12x=6x-6,

therefore it will become

x³-6x²+12x-6x-8+6=0,

x³-6x²+6x-2=0