Question

Please answer question no. 2

Answer 1

Step-by-step explanation:

let sin @ be a and cos @ be b.

i am doing this for my own convenience.

so we have

a+b/b-a - a-b/a+b

by simply subtracting we have

(a+b)^2 -(a-b)^2 /b^2-a^2

now expanding

a^2 +b^2+2ab-(a^2+b^2-2ab) /b^2-a^2

here a^2 +b^2=1( sin^2+cos^2=1)

1+2ab-1+2ab/b^2-a^2

=4ab/b^2-a^2

cos^2@-sin^2@=cos2@

so our eqn is

4sin@cos@/cos2@

=2sin2@/cos2@

=2tan2@

still have problen ask me in comment