Math, asked by Riya111134, 1 year ago

Please answer question no. 27

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Answered by sssrohit005p4c0ey

2

ps=ps (GIVEN)
angle SPQ=ANG RQP (GIVEN)
PQ=PQ (COMMON)

HENCE triangle PQS CONGRUANT TO TRIANGLE QPR....
QS=PR(CPCT)
ANG PQS=ANG QPR(CPCT)

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