Please answer question no. 27
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ps=ps (GIVEN)
angle SPQ=ANG RQP (GIVEN)
PQ=PQ (COMMON)
HENCE triangle PQS CONGRUANT TO TRIANGLE QPR....
QS=PR(CPCT)
ANG PQS=ANG QPR(CPCT)
angle SPQ=ANG RQP (GIVEN)
PQ=PQ (COMMON)
HENCE triangle PQS CONGRUANT TO TRIANGLE QPR....
QS=PR(CPCT)
ANG PQS=ANG QPR(CPCT)
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