please answer question no 3
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Let digit at unit place is x
digit at tens place is y
Number = 10y+x
According to the question
10y+x+y+10x =110
11x+11y=110
x+y=10 ....(1)
x-y=6 ..... (2)
Adding equation (1) and equation(2) we get
2x=16
x=8
substitute the value of x in equation (1)
8+y=10
y=10-8
y=2
Number=28
digit at tens place is y
Number = 10y+x
According to the question
10y+x+y+10x =110
11x+11y=110
x+y=10 ....(1)
x-y=6 ..... (2)
Adding equation (1) and equation(2) we get
2x=16
x=8
substitute the value of x in equation (1)
8+y=10
y=10-8
y=2
Number=28
shreyaarora646p9zoms:
Here, y-x can also be 2, so 2 answers will be formed.
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Hope it help☺ see attachment!
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