Math, asked by tiwarihimanshu1678, 1 year ago

Please answer question no. 4

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Answered by sandy1816

1

Step-by-step explanation:

sin7θ+sin4θ+sinθ=0

2sin4θcos3θ+sin4θ=0

sin4θ(2cos3θ+1)=0

sin4θ=0 or 2cos3θ+1=0

4θ=nΠ , n∈Z or cos3θ=-1/2

θ=nΠ/4 or cos3θ=cos(Π-Π/3)

=cos2Π/3

3θ=2nΠ±2Π/3

θ=2nΠ/3±2Π/6

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