please answer question number 16 by step
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Answered by
2
The time taken by ball A to reach Ball B
=
During the time interval 0 to 6s
ball covers a distance of 20m upto ball B(which takes 4 sec) and in the next 2 secs it covers
Net displacement
=
hence average velocity
=
=2m/s
HOPE THIS HELPS YOU..........
=
During the time interval 0 to 6s
ball covers a distance of 20m upto ball B(which takes 4 sec) and in the next 2 secs it covers
Net displacement
=
hence average velocity
=
=2m/s
HOPE THIS HELPS YOU..........
Answered by
1
time taken for going 20 m=(20/5)sec=4sec
distance in next 2sec=(4×2)m=8m
So,total displacement=(20-8)m=12m
So, velocity (net)=(12/6)m/s=2ms^-1
distance in next 2sec=(4×2)m=8m
So,total displacement=(20-8)m=12m
So, velocity (net)=(12/6)m/s=2ms^-1
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