Math, asked by maitri24, 11 months ago

Please answer question number 2 and 3 step by step

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Answers

Answered by Anonymous286
1
2x-3y=2
2x+3y=14
Adding both equation
4x=16
x=4
put x=4 in equation 1
2(4)-3y=2
8-2=3y
6=3y
y=2
Taking Lhs
x*y=4*2
=8
=RHS
hence priced
Now for the 3rd sum
3p+5q=11(given)
squaring both sides
9p^2+2*3*5pq+25q^2=121
now pq=2(given)
putting the above value in the equation
9p^2+2*3*5*2+25q^2=121
9p^2+60+25q^2=121
9p^2+25q^2=121-60
=61
so the answer is 61
Hope it helps
:)
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