Question

please answer question number 8 it's urgent for my exam

Answer 1

let the cost of one table be x and of 1 chair be y.
5x-8y=150
putting y equal to 240
5x-1920=150
5x=150+1920=2070
×=2070÷5=414ans...
HOPE IT HELPS YOU '_'

Answer 2

let the cost of one table be x and the cost of one table be y
then according to the question....the difference between the cost of 5 tables and 8 chars is 150
so... that means
$5x - 8y = 150$
this is the required linear equation
and in order to find the cost of one table if the cost of one chair is 240....we just need to replace y in the equation above by 240 since y represents the cost of one chair
putting 240 in place of y we get
$5x - 8(240) = 150$
further solving it gives:
$5x = 2070$
$x = \frac{2070}{5}$
$x = 414$
thus the cost of one table is 414 if the cost of one chair is 240