Question

✌PLEASE ANSWER✌
✌ QUESTION OF DIMENSIONAL ANALYSIS✌

Answer 1

P= ax^2-bt 

where P is pressure,x is distance and t is time.

Dimension of Pressure = [M L^-1 T^ -2.].

P=ax^2 and P=bt [By dimensional analysis rule]

Substitute dimensions:

P=ax^2

ML^-1T^-2=a L^2

Dimension of a = [ML^-3T^-2].

P= bt

ML^-1T^-2=b T

Dimension of b = ML^-1T^-3.

Now ,

Dimension of a x b :

ML^-3T^-2 x Ml^-1T^-3

=M^2L^-4T^-5.

Dimension of a/p:

ML^-3T^-2/ML^-1T^-2

= L^-2.


Hope it helps u!!!!

Answer 2

deminsion of a/p is L^-2