Question

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Answer 1

Answer:

$perimeter \: of \: rectangle = 2 \times (l + w) \\ length = 7cm \\ height = 25cm \\ = 2 \times (7 + 25)cm \\ 2 \times 32 = 64 \\ hence \: perimeter \: of \: rectangle \: is \: 64$

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Answer 2

Answer:

62 cm

Step-by-step explanation:

Given:-

BCDE is a rectangle

CE=25cm

CD=7cm

To find:-

Perimeter of BCDE

Solution:-

In triangle CDE

(CE)²=(CD)²+(ED)² {By Pythagoras theorem}

25²=7² +(ED)²

625 =49 + (ED)²

625-49 =(ED)²

576=(ED)²

√576 =ED

24 =ED

Perimeter of rectangle=2×(l+b)

=2 ×(24+7)

=2×31

=62 cm(Ans)

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