Question

Please answer quick!!!
Q1. 2 runners r training at the same time on a 720 m long.; round running track. They run with constant speed in opposite directions. The first runner needs four minutes for one lap; the second five minutes.How.many meters does the second runner run in between two consecutive meeting of the two runners?
only answer if u know!!​

Answer 1

Answer:

Step-by-step explanation:

We will start by finding velocities of both the runners:

Let the runners be named as A and B.

$V_{A}$ = 720 / 4*60

                         = 3 m/sec

$V_{B}$ = 720 / 5*60

                         = 2.4 m/sec

Time at which they meet for first time:

$S_{A}$ + $S_{B}$ = 720 m

$V_{A}$*t + $V_{B}$*t = 720

t*($V_{A}$ + $V_{B}$) = 720

t*5.4 = 720

t = 400/3 secs

Then they will meet again at same point at 800/3 secs

As it is following an AP cause speeds are constant

We have to find distance covered by B in two consecutive meetings

This is equal to Distance covered by B in 400/3 secs

i.e. 2.4*400/3

   = 320 m.......<<<<Answer.

I Hope this will help you...

Answer 2

let the two runners be A and B

with Va and Vb as their velocities

velocity=distance/time

Va=720/4*60

=3m/s

Vb=720/5*60

=2.4m/s

Let the 2 runners start from a common position X and meet at Y

so the 2 consecutive meetings happen at X and Y

so we have to find time of meeting at Y as we know that of X (which is t=0)

720=Va*t+Vb*t

t(5.4)=720

t=133.33 or t=720/5.4

therefore distance travelled by B =Vb*t

=2.4*720/5.4

=319.99m

=320m