Question

please answer quick with explanation​

Answer 1

Answer:

It's answer is 110cm^2

Step-by-step explanation:

Area of shaded portion = Area of rectangle - Area of 2 triangles (AFE & BCE)

Area of rectangle = L X B = 18cm X 10 cm =180cm^2

Ate of triangle AFE = 1/2 X Base X height =1/2x10cmx6cm =30cm^2

Area of triangle BCE = 1/2 X Base X height =1/2x10cmx8cm =40cm^2

Therefore, Area of Shaded portion =180cm^2-(30cm^2 + 40cm^2)

=110cm^2

Hope it helps you

Answer 2

Step-by-step explanation:

Area of rect (ABCD)

= L×B

= (18 ×10)cm

= 180 cm

Now, according to pythagorus theoram,

FE² = AF² + AE²

FE² = 6² + 10²

FE = √(36 + 100)

FE = √136

FE = 11 cm (approx)

Next,

EC² = EB² + BC²

EC² = 8² + 10²

EC = √(64 + 100)

EC = √(164)

EC = 12 cm (approx)

So, Area of shaded portions (quadrilateral)

= (½) × diagonal length × sum of the length of the perpendiculars drawn from the remaining two vertices.