Math, asked by nkumar9799, 8 months ago

please answer quickly​

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Answered by nishant3793
1

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here is your answer hope it help you

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Answered by AditiHegde
0
  • Given
  • \dfrac{2(3y-4)+6}{3y-(4+5y)} =\dfrac{3}{5}
  • \dfrac{6y-8+6}{3y-4-5y} =\dfrac{3}{5}
  • \dfrac{6y-2}{-2y-4} = \dfrac{3}{5}
  • 30y - 10 = -6y - 12
  • 30y + 6y = -12 + 10
  • 36y = -2
  • y = \dfrac{-2}{36}
  • y = \dfrac{-1} {18}
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