please answer quickly homework is taking forever
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we know that cos^2A=1-sin^2A
thus,
cosA=√(1-sin^2a).....(i)
tan A=sinA/cosA
tan A=sin A/(√1-sin^2A). (using (i))
sec A =1/ cos A
thus,
sec A =1/√1-sin^2A
thus,
cosA=√(1-sin^2a).....(i)
tan A=sinA/cosA
tan A=sin A/(√1-sin^2A). (using (i))
sec A =1/ cos A
thus,
sec A =1/√1-sin^2A
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