Question

Please answer quickly.Irrelevant answers would be reported. Answer quickly and correctly and I'll mark your answer as brainly: Ques) find total amount of heat recqired to convert 2kg of ice at -10°C to 100°C of steam.Specific heat capacity of ice=4200 J kg^-1 K^-1 Specific heat capacity of Water= 2100 J kg^-1 K^-1 Specific latent heat of fusion of ice=33600 J kg^-1 K^-1 Specific latent heat of vaporization of water=226800 J kg^-1 K^-1

Answer 1

Answer:

1024.8kJ

Explanation:

first bring the ice at -10°C to 0°C ice

heat=mass(kg)×specific heat capacity×change in temperature(Kelvin or celcius)

=2×4200×10

=84000J

now for conversion into water

heat=2×33600=67200J

for bringing 0°C water into 100°C water

heat=2×2100×100=420000J

now for conversion into steam

heat=2×226800=453600J

total heat=84000+67200+420000+453600=1024800J

=1024.8kJ