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a= 2√5 , b= -3 c = -√5
ac = -10
So, we can write the equation as 2√5x² -5x +2x -√5 =0
Taking factors ,
x√5( 2x - √5) + 1(2x-√5)=0
Taking common factors we get,
(x√5+1)(2x-√5) = 0
x= -1/√5 or √5/2
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clearly the required value of x is
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