Question

Please answer quickly its urgent

Answer 1

Answer:

52 4.2

Step-by-step explanation:

Given,

AC=25cm,

AE=15cm,

BC=7cm

Applying Pythagoras theorem in triangle AEC,

⇒AC

2

=AE

2

+EC

2

⇒EC

2

=25

2

−15

2

⇒EC

2

=625−225=400

⇒EC=20cm

Now, EB=EC−BC=20−7=13cm

Area of triangle AEC,

=

2

1

×AE×EC

=

2

1

×15×20=150cm

2

Now, Area of triangle AEB,

=

2

1

×AE×EB

=

2

1

×15×13=97.5cm

2

Thus,

area of triangle ABC = Area of triangle AEC - Area of triangle AEB

=150−97.5

=52.5cm

2

Now, again area of triangle ABC=

2

1

×BD×AC

⇒52.5=

2

1

×BD×AC

⇒52.5=

2

1

×BD×25

⇒BD=

25

52.5×2

=4.2cm

Therefore, 52.5 square centimeters is the area of triangle ABC and length is DB=4.2cm.