Question

please answer quickly .....
Mr. Lalit invested 5000 at a certain rate of interest, compounded annually for two years. At the end of first year it amounts to 5325. Calculate
(i) the rate of interest.
(ii) the amount at the end of second year, to the nearest rupee.​

Answer 1

P=5000

Amount at the end of first year=5325

S.I=A-P

=5325-5000

=325

1)RATE=SI×100÷P×T

=325×100÷5000×1

=325÷50

=6.5%p.a

2)amount at the end of the second year= a(1+r/100)^2

= 5000(1+6.5/100)^2

=5000×1065/1000×1065/1000

=1065×1065/200

=213×213/8

=45399/8

=5671

Answer 2

Answer:

REFER THE ATTACHMENT GIVEN ABOVE