Question

Please answer quickly!! Thanks!

Answer 1

$Given Equation is \frac{4}{x} - 3 = \frac{5}{2x+3}$

LCM = x(2x + 3)

$\frac{4}{3} * x(2x + 3) - 3x(2x + 3) = \frac{5}{2x+3} * x(2x + 3)$

$4(2x+3) -3x(2x+3)= 5x$

8x + 12 - 6x^2 - 9x = 5x

-6x^2 - x + 12 = 5x

-6x^2 - 6x + 12 = 0

-6(x^2 + x - 2) = 0

x^2 + x - 2 = 0

x^2 - 1x + 2x - 2 = 0

x(x - 1) + 2(x - 1) = 0

(x - 1)(x + 2) = 0

x = -2 (or) x = 1.


Hope this helps!