Question

please answer step by step​

Answer 1

$given \: \: question \: \: is \: \: \\ \: \: x {}^{5} \div \frac{1}{x {}^{ - 3} } = 49 \\ \\ = > \frac{x {}^{5} }{ \frac{1}{x {}^{ - 3} } } = 49 \\ \\ = > \frac{x {}^{5} \times x {}^{ - 3} }{1} = > 49 \\ \\ = > x {}^{(5 - 3)} = 49 \\ \\ = > x {}^{2} = 49 \\ \\ x = \sqrt{49} \\ \\ x = 7$