Question

please answer step by step​

Answer 1

Answer:

$\longrightarrow\rm \Bigg \{P + \dfrac{a}{V^2}\Bigg \} (V - b) = RT$

• P = Pressure
• V = volume
• We need to find the Dimensions of constant a.

$\longrightarrow\rm [P] = \dfrac{[a]}{[V^2]}$

$\longrightarrow\rm [M^1L^{-1} T^{-2}] = \dfrac{[a]}{[M^0L^3T^0]^{2} }$

$\longrightarrow\rm [M^1L^{-1} T^{-2}] = \dfrac{[a]}{[M^0L^6T^0]}$

$\longrightarrow\rm [a] = [M^1L^{-1} T^{-2}] [M^0L^6T^0]$

$\longrightarrow \underline{ \boxed{\orange{\bold{ [a] = [M^1L^{5} T^{-2}] }}}}$

Hence, the Option (C) is the correct answer.