Question

please answer step by step by solving​

Answer 1

HOW TO SOLVE?

$(a) \: \: \: \: \: \: \: {2}^{0} - 2 {}^{ - 3} \\ 1 - \frac{1}{ {2}^{3} } \\ 1 - \frac{1}{8} \\ \frac{8 - 1}{8} = \frac{7}{8} \\ (b) \: \: \: \: ( \frac{1}{4} ) {}^{ - 3} = ( {4})^{ 3} \\ 4 \times 4 \times 4 = 64$

$(c) \: \: \: \: ( \frac{2}{7} ) {}^{ - 1} + (7) {}^{ 0} \\ ( \frac{7}{2} ) + 1 \\ \frac{7 + 2}{2} = \frac{9}{2} \\ 4 \frac{1}{2}$

$(d) \: \: \: \: (8) {}^{ - 6} \times ( {8)}^{4} \\ (8) {}^{ - 6 + 4} \\ (8) {}^{ - 2} \\ ( \frac{1}{8} ) {}^{2} \\ \frac{1}{64}$

$(e) \: \: \: 7 {}^{ - 10} \div {7}^{ - 10} \\ (7) {}^{ - 10 - ( - 10)} \\ {(7)}^{ - 10 + 10} \\ ( {7)}^{0} = 1$

$(f) \: \: \: ((4) {}^{11} ) {}^{0} \\ (4) {}^{11 \times 0} \\ (4) {}^{0} = 1$

$(g) \: \: \: \: ({3}^{ - 9} ) {}^{4} \times (3 {}^{ - 5} ) {}^{ - 7} \\ 3 {}^{ - 9 \times 4} \times 3 {}^{ - 5 \times ( - 7)} \\ 3 {}^{ - 36} \times {3}^{35} \\ {3}^{ - 36 + 35} \\ (3) {}^{ - 1} \\ \frac{1}{3}$

$(h) \: \: \: \: ( {2}^{5} ) {}^{ - 6} \div ( {2 }^{ - 9}) {}^{3} \\ (2) {}^{ - 6 \times 5} \div (2) {}^{ - 9 \times 3} \\ (2) {}^{ - 30} \div (2) {}^{ - 27} \\ (2) {}^{ - 30 - ( - 27)} \\ (2) {}^{ - 3 0 + 27} \\ (2) {}^{ - 3} \\ (\frac{1}{2} ) {}^{3} = \frac{1}{8}$

HAVE A NICE DAY!!!

HOPE IT HELPS YOU!!!