Question

Please answer step by step explanation​

Answer 1

Required Answer:-

Before coming to answer,

The rise of water was due to addition of rubber stopper which was equal to its own volume apart from the water.

Hence,

Volume of the stopper = Final volume - Initial volume.

i.e. 84 ml - 46 ml

= 38 ml

And,

Mass of the stopper = 45g

We know that,

$\boxed{\rm{Density = \dfrac{mass}{density}}}$

➛ Density of stopper = 45g/38ml

➛ Density of stopper = 1.842 g/ml

Since, it's a solid

➛ Density of stopper = 1.842 g/cm³ (approx.)

Answer 2

Answer:

Given :-

• A measuring cylinder contains water up to the level of 46 ml.
• The water level rises to 84 ml, when a rubber stopped is emerged into it.
• The mass of the rubber stopper is 45 g.

To Find :-

• What is density of the rubber stopper.

Solution :-

First, we have to find the total volume of stopper :

➳ Volume of Stopper = (84 - 46) ml

➲ Volume of Stopper = 38 ml

Now, we have to find the density of stopper :

As we know that :

✭ Density Formula :

$\mapsto \sf\boxed{\bold{\pink{Density =\: \dfrac{Mass}{Volume}}}}$

Given :

• Mass = 45 g
• Volume = 38 ml

According to the question by using the formula we get,

$\implies \sf Density =\: \dfrac{45}{38}$

$\implies \sf\bold{\red{Density =\: 1.1842\: g/ml}}$