Question

Please answer step by step...
No spamming or else answer will be reported​

Answer 1

Answer:

(4) 1

Explanation:

$\frac{2 {}^{n + 4} - 2(2 {}^{n} )}{2(2 {}^{n} + 3)} + 2 {}^{ - 3} \\ \\ = \frac{2 {}^{n} .2 {}^{4 } - 2.2 {}^{n} }{2.2 {}^{n}.2 {}^{3} } + 2 {}^{ - 3} \\ \\ = \frac{2 {}^{n} (2 {}^{4} - 2) }{2.2 {}^{n} .2 {}^{3} } + 2 {}^{ - 3} \\ \\ = \frac{2 {}^{4} - 2}{2.2 {}^{3} } + 2 {}^{ - 3} \\ \\ = \frac{16 - 2}{ 2\times 8} + 2 {}^{ - 3} \\ \\ = \frac{14}{16} + 2 {}^{ - 3} \\ \\ = \frac{14}{16} + \frac{1}{2 {}^{3} } \\ \\ = \frac{14}{16} + \frac{1}{8} \\ \\ = \frac{7}{8} + \frac{1}{8} \\ \\ = \frac{7 + 1}{8} = \frac{8}{8} = 1$

Answer 2

Answer:

I purple you too and ya it's on 4th December and please don't tell these things now