Question

please answer
$find value f \: x \: it \\ tam + tam2x \: tam3x \: = tamx \: tam2x \: tam3x$

Answer 1

tan x+tan 2x+ tan 3x=tan x.tan 2x. tan 3x

tan x+tan 2x=tan 3x (tan 2x. tan x -1)

tan 3x=tan x +tan 2x/(tan x.tan 2x-1)

tan 3x = -tan 3x

tan 3x = tan(n$\pi$-x)

x=$\frac{n\pi }{6}$ where n belong to an integer