Math, asked by jasmin239, 11 months ago

please answer th8s question raisins urgent , brainly experts please answer fast its urgent.....

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Answered by siddhartharao77
1
Given : x = 9 - 4 \sqrt{5} .

= \ \textgreater \   \frac{1}{x} =  \frac{1}{9 - 4 \sqrt{5} } *  \frac{9 + 4 \sqrt{5} }{9 + 4 \sqrt{5} }

= \ \textgreater \   \frac{9 + 4 \sqrt{5} }{(9)^2 - (4 \sqrt{5} )^2}

= \ \textgreater \   \frac{9 + 4 \sqrt{5} }{81 - 80}

= \ \textgreater \  9 + 4 \sqrt{5}

Now,

= \ \textgreater \  x +  \frac{1}{x} = 9 - 4 \sqrt{5} + 9 + 4 \sqrt{5}

= \ \textgreater \  9 + 9

= \ \textgreater \  18

On Squaring both sides, we get

= \ \textgreater \  (x +  \frac{1}{x} )^2 = (18)^2

= \ \textgreater \  x^2 +  \frac{1}{x^2} + 2 = 324

= \ \textgreater \  x^2 +  \frac{1}{x^2} = 324 - 2

[tex]= \ \textgreater \ x^2 + \frac{1}{x^2} = 322. [/tex]




Hope this helps!

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jasmin239: Thanku very much
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