Question

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Answer 1

Answer:

Given, To prove : ∆GCB ~= ∆ DCE

IN ∆ GCB & ∆ DCE

BC = CE ( Given in the question)

Angle 1 = Angle 2 ( Given in the question)

So,

Angle GCB = Angle DCE ( Vertically opposite angles )

Hence ,

∆GCB ~= ∆ DCE ( A.A.S.)

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