please answer the 10th question
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Heat supplied is 12.5kcal
internal energy is 10500/4200=2.5
From first law of thermodynamics
dQ= dU +dW
12.5-2.5
dW=10Kcal
internal energy is 10500/4200=2.5
From first law of thermodynamics
dQ= dU +dW
12.5-2.5
dW=10Kcal
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