Question

Please answer the 15th 16th and 17th question

Answer 1

Let the cost of one chair be represented by x and cost of one table by y
as per the question
we get eqn 1 to be
3x + 5y 15500
and eqn 2 to be
5x + 6y = 11900
by equating and simplifying we get y ie the cost of one table to be Rs. 2200
by substituting y value in eqn 1 we get x ie cost of one chair to be Rs. 1500
therefore the cost of one chair and one table is Rs. 3700
This is 15th answer



The 16th answer starts here
eqn 1 =19x + 8y = 1347
eqn 2=21x + 4y = 961
by equating and simplifying 1 and 2 we get x to be 25
by substituting x value in eqn 1 we get y to be 109
therefore 4x + 5y = 645




The 17th answer starts here
Let the cost of 1kg sugar be x and cost of 1kg wheat be y
eqn 1 =5x + 6y = 320
eqn 2=6x + 5y = 340
by equating and simplifying eqn 1 and 2 we get y ie cost of 1kg wheat to be Rs.20
by substituting y value in eqn 1 we get x ie cost of 1kg sugar to be Rs.40