Question

please answer the 16th and 17th question...​

Answer 1

Answer:

$\alpha + \beta = \frac{ - b}{a} = \frac{ - ( - 6)}{2} = 3 \\ \alpha \beta = \frac{c}{a} = \frac{3}{2} \\ ( \frac{ \alpha }{ \beta } + \frac{ \beta }{ \alpha } ) + 3( \frac{1}{ \alpha } + \frac{1}{ \beta } ) + 2 \alpha \beta \\ = ( \frac{ { \alpha }^{2} + { \beta }^{2} }{ \alpha \beta } ) + 3( \frac{ \beta + \alpha }{ \alpha \beta } ) + 2 \alpha \beta \\ = \frac{ { (\alpha + \beta )}^{2} - 2 \alpha \beta }{ \alpha \beta } + 3( \frac{ \alpha + \beta }{ \alpha \beta } ) + 2 \alpha \beta \\ = \frac{ {3}^{2} - 2( \frac{3}{2} ) }{ \frac{3}{2} } + 3( \frac{3}{ \frac{3}{2} } ) + 2( \frac{3}{2} ) \\ = \frac{9 - 3}{ \frac{3}{2} } + 3 \times 2 + 3 \\ = \frac{6}{3} \times 2 + 6 + 3 \\ = 4 + 9 \\ = 13$

Answer 2

HERE IS A SMALL ANSWER FOR YOU..

HOPE ITS HELPFUL...