Please answer the 1st question with explaination fast!!!!!!!!!!!!!!!!!!!!!!!
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in ∆ADC ∠ACD =∠DAC=(180°-∠ADC)/2=(180°-100°)/2=40° therefore ∠ BAC=∠ACD=40°
∠ABC=100
the point at which angle is 33° should be E
∠DAE=68°-40°=28°
x=360°-{33°+28°+(360°-100°)}=360°-321°=39°
∠ABC=100
the point at which angle is 33° should be E
∠DAE=68°-40°=28°
x=360°-{33°+28°+(360°-100°)}=360°-321°=39°
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