Please answer the 3rd Question with the help of that triangle diagram ( Only 3rd question )
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Answer:
Q1 angle CDB = angle BEC .......... each angle 90°
BC= BC ...... common side
BD= EC .... given
Q2 same as Q1
Q3 yes it's equal because of CPCT
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Step-by-step explanation:
Given : BD=CE
i . NOW, In CBD and BCE,
BD=CE (given)
BC (common base)
‹BDC=‹CEB [each is right angle]
ii . yes, CBD and BCE are congruent (by S-A-S axiom of congruency)
iii. yes, ‹DCB=‹EBC ( corresponding sides of congruent triangle )
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