Question

Please answer the 7th and 8th question. Thank youuu in advance

Answer 1

solution:

7) 2x= 100

=> x= 50°

8) in Traiangle OAP.

=> op^2+ Ap ^2= Ao^2

=> 9+16= Ao^2

=> Ao^2= 25

=> AO= 5cm

Now,in Traiangle AOC

=> oc^2= ac^2+ ao^2

=> 49= ac^2+ 25

=> 24= ac^2

=> ac= 2root6 cm

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Answer 2

HEYA!!

HERE'S YOUR ANSWER
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Q.7

In ∆POQ,

OPQ+POQ+OQP = 180°

But, OPQ=OQP [radii of same circle]

So, 2.OPQ + 100° = 180°

2.OPQ = 80°... So, OPQ = 40°

Now, angle P = 90° [ tangent on a circle ]

So, OPQ + x = 90°

x = 90° - OPQ = 90° - 40°

Therefore, x = 40°.
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Q.8

Here,AP = PB [ perpendicular from the centre to the chord bisects the chord]

So, AP = 4cm

Applying PGT in ∆AOP, we get

OA = √(9+16) = √25 = 5cm

Similarly, applying PGT in ∆AOC, we get

OC^2 = AC^2 + OA^2

or AC^2 = OC^2 - OA^2

= 7^2 - 5^2 = 49 - 25 = 24cm

So, AC = √24

Therefore, AC = 2√6 cm.

{NOTE: PGT means Pythagoras Theorem}
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