Math, asked by rimshafatima2009, 1 month ago

Please answer the 8 question

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Answers

Answered by anwarikhatoonmuz
1

Answer:

Length of wall= 4.5m

Breadth of the wall= 3.6m

Length of the door =2m

Breadth of the door= 1m

Area of the wall = l\times b=4.5m\times3.6m=\ 16.20m^2l×b=4.5m×3.6m= 16.20m

2

Area of the door = l\times b=2m\times1m=2m^2l×b=2m×1m=2m

2

Therefore area of the wall to be white washed= Area of the wall - Area of the door

=Rs\ 14.20\times20=Rs\ 284.00=Rs 14.20×20=Rs 284.00

Hence, the required area= 14.20m^214.20m

2

and the required cost= Rs 284

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