Question

please answer the 9th question

Answer 1

given QT is the inspector of <PQR
therefore <PQT =<TQR=x
given RT is the bisector of<PRS
therefore <PRT = < TRS = y

In triangle QTR
<QTR + X + 180-y = 180(A.S.P)
<QTR = Y - X
IN TRIANGLE QPR
<QPR + 2x +180-2y = 180(A.S.P)
<QPR=2y-2x
= 2(y-x)

Using first set
<QPR = 2<QTR
SO,<QTR = 1/2<QPR