Question

Please answer the 9th question

Answer 1

Angle be © and (90-©) ©=theta.

Therefore,tan©=h/a

Tan(90-©)=h/b

Tan(90-©)= sec©

Tan©× sec©=1

Tan©×sec©=h/a×h/b=h^2/ab

Ab=h^2. ( H^2 is h ka square)

H=√ab. Hence proved.