Question

please answer the above​

Answer 1

Answer:

1/3

Step-by-step explanation:

Let x- y = a

     y-z = b

    z-x =c

we can see a + b + c=0

we know, if a + b + c =0

then a³ + b³ + c³ = 3abc

Here, 3abc  = 3 (x-y)(y-z)(z-x)

Substituting,

$\frac{3(x-y)(y-z)(z-x)}{9(x-y)(y-z)(z-x)}\\ \\similar cancel,\\\\\frac{1}{3}$

Ans 1/3