Question

please answer the above problem ....​

Answer 1

Answer:

2X²-2√2X+1 = 0

==> A = 2 , B = -2√2 , C = 1

==> X = (-B ±√(B)²-4AC)/2A

==> x = -(-2√2) ± √(-2√2)² - 4(2)(1)/ 2(2)

==> 2√2 ± √8 - 8 / 4

==> 2√2 ± 0 /4

==> 2√2/4

==> √2/2

===> √2 / √2*√2

==> 1/√2 = 0

SO, ANSWER ==> 1/√2 , 1/√2

Answer 2

Answer:

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Step-by-step explanation:

$2x^{2} -2\sqrt{2}x+1=0\\\\=>A=2,B=-2\sqrt{2},C=1\\=>x=(-B+-\sqrt{B^{2} }-4ac/2a\\=>x=-(-2\sqrt{2}) +-\sqrt{(-2\sqrt{2)} }^{2}-4(2)(1)/(2*1)\\=>2\sqrt{2}+-\sqrt{8}-8/4\\=>2\sqrt{2}+-0/4\\=>2\sqrt{2} /4=>\sqrt{2}/2\\ =>1/\sqrt{2}=0$