Question

Please answer the above question ​

Answer 1

Answer:fe2 03 +co=3feo+co2

Explanation:

Answer 2

Explanation:

$\tt {Fe}_{2}{O}_{3} + 3CO \longrightarrow 2Fe + 3C{O}_{2} \:\:\:\: \Delta {H}_{1} = -26 \: KJ \\ \\ \tt FeO + CO \longrightarrow Fe + C{O}_{2} \:\:\:\: \Delta {H}_{2} = -16 \:KJ \\ \\ \tt Observe\:the\: required\:reaction\:and\:try\:to\:make\:the\:given\: reaction\:in\:that\:way \\ \\ \tt Reversing\:the\:{2}^{nd} \: reaction \\ \\ \tt Fe + C{O}_{2} \longrightarrow FeO + CO \:\:\:\: \Delta {H}_{3} = +16 \:KJ \\ \\ \tt Now\:by\: multiplying\:by\:2 \\ \\ \tt 2Fe+ 2C{O}_{2} \longrightarrow 2FeO + 2CO \:\:\:\: \Delta {H}_{4} = 32 kJ \\ \\ \tt Now \: adding\: {H}_{1}\:and\:{H}_{4} \\ \\ \tt {Fe}_{2}{O}_{3} + CO \longrightarrow 2FeO + C{O}_{2} \: \:\:\: \Delta H = +6\:kJ \\ \\ \tt \boxed{\bold{\underline{\red{\tt So\:the\:\Delta H\:for\:required\:reaction\:is\:+6\:kJ}}}}$