Question

Please answer the above question​

Answer 1

Answer:

let the first natural no. is x

and the second no is (x-4)

now

(x)^2 + ( x-4 )^2 = 58

x^2 + x^2 + 16 - 8x = 58

2x^2 - 8x + 16 - 58 = 0

2x^2 - 8x - 42 = 0

x^2 - 4x - 21 = 0

x^2 + 3x - 7x -21 = 0

x ( x + 3 ) - 7 ( x + 3 ) = 0

( x - 7 )( x + 3 ) = 0

x = 7, -3

-3 is rejected because the no.s are natural no.s

so x = 7

and the second no. is ( x-4 ) = 7-4 = 3

Answer 2

Answer:

Option 4th is the correct answer.