Question

please answer the above question...​

Answer 1

Answer:

Given: Type of unit cell is ccp.

Edge length (a) = 353.6 pm = 3.536 x 10-8 cm = = Volume (V) of Al = 1.00 cm3 =

To find:

1. Radius of Al atom (r)

2. Number of unit cells in 1.00 cm3 of Al

Formulae:

1. For ccp (fcc) unit cell, r = 0.3535 a

2. Number of unit cells in volume (V) of metal =

V

Calculation:

1. Using formula (i),

r = 0.3535 a

.. r = 0.3535 x 353.6 = 125 pm

2. Using formula (ii),

Number of unit cells in volume (V) of metal =

V

a3

.. I Number of unit cells in 1.00 cm3 of AI =

1.00

3 (3.536 x 10-8)*

2.26 x 10^22

1. Radius of Al atom (r) is 125 pm.

2. Number of unit cells in 1.00 cm3 of Al is 2.26

10^22