please answer the above question.....
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Answered by
2
Answer:
12
Step-by-step explanation:
Let the no. be x , (x + 2)
x² + (x + 2)² = 244
=> X² + x² + 4 + 4x = 244
=> 2x² + 4x - 240= 0
=> X² + 2x - 120 = 0
=> X² + 12x - 10x - 120 = 0
=> X(x + 12) - 10(x + 12) = 0
=> (X - 10)(x + 12)
=> X = 10 , -12
Non be 10 , (10 + 2) = 12
HOPE IT HELPS....
Answered by
4
Heya
______________________________
Cosecutive Numbers :- Numbers lying after one another.
Let the ist Number be x
it's even consecutive number is ( x + 2 )
ACCORDING TO THE QUESTION
x² + ( x + 2)² = 244
=>
x² + x² + 4 + 4x = 244
=>
2x² + 4x - 240=0
=>
x² + 2x - 120=0
=>
x² + 12x - 10x - 120 = 0
=>
x ( x + 12 ) - 10 ( x + 12 ) = 0
=>
x = -12 OR x = 10
For x = 10
it's even consecutive number is 12
For x = -12
it's even consecutive number is -10
So the numbers are
10 And 12 OR -10 And -12
______________________________
Cosecutive Numbers :- Numbers lying after one another.
Let the ist Number be x
it's even consecutive number is ( x + 2 )
ACCORDING TO THE QUESTION
x² + ( x + 2)² = 244
=>
x² + x² + 4 + 4x = 244
=>
2x² + 4x - 240=0
=>
x² + 2x - 120=0
=>
x² + 12x - 10x - 120 = 0
=>
x ( x + 12 ) - 10 ( x + 12 ) = 0
=>
x = -12 OR x = 10
For x = 10
it's even consecutive number is 12
For x = -12
it's even consecutive number is -10
So the numbers are
10 And 12 OR -10 And -12
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