Math, asked by cutipie16, 1 year ago

please answer the above question.....

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Answered by candynithish
2

Answer:

12

Step-by-step explanation:

Let the no. be x , (x + 2)

x² + (x + 2)² = 244

=> X² + x² + 4 + 4x = 244

=> 2x² + 4x - 240= 0

=> X² + 2x - 120 = 0

=> X² + 12x - 10x - 120 = 0

=> X(x + 12) - 10(x + 12) = 0

=> (X - 10)(x + 12)

=> X = 10 , -12

Non be 10 , (10 + 2) = 12

HOPE IT HELPS....

Answered by Anonymous
4
Heya

______________________________

Cosecutive Numbers :- Numbers lying after one another.

Let the ist Number be x

it's even consecutive number is ( x + 2 )

ACCORDING TO THE QUESTION

x² + ( x + 2)² = 244

=>

x² + x² + 4 + 4x = 244

=>

2x² + 4x - 240=0

=>

x² + 2x - 120=0

=>

x² + 12x - 10x - 120 = 0

=>

x ( x + 12 ) - 10 ( x + 12 ) = 0

=>

x = -12 OR x = 10

For x = 10

it's even consecutive number is 12

For x = -12

it's even consecutive number is -10

So the numbers are

10 And 12 OR -10 And -12
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