Question

Please answer the above question.

Answer 1

$\huge{\mathfrak{HEYA\:MATE\:!!}}$

please refer to the attachment.

нσρє нєℓρѕ !❤️❤️

Answer 2

-2×96500×0.236

=-45.55kgmol^-1

also∆r G°=-2.303 RT log Kc

log kc =∆r G°/2.303Rt= -45.55/2.303×8.314×10^-3×298 =7.983

Kc =antilog (7.983)

=9.616×10^7