Math, asked by anisha3092006, 10 months ago

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Answered by bharatahlawat4142
20

Answer:

1.)root72+root48=   6 \sqrt{2}  + 4 \sqrt{3}  \\  = 6 \times 1.414 + 4 \times 1.732  \\ = 8.49 + 6.93  \\  = 15.42(approx) \\  \\  \\  \\ 2.)  \sqrt{125}  \div  \sqrt{64}  \\  = 5 \sqrt{5}  \div 8 \\  = 11.1803398875 \div 8 \\  =3.95(approx.)

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Answered by StarrySoul
40

Given :

\sf \sqrt{2}  = 1.414

\sf \sqrt{5}  = 2.236

\sf \sqrt{3}  = 1.732

To Find :

1) \sf \:  \sqrt{72} +  \sqrt{48}

2) \sqrt{ \dfrac{125}{64} }

Solution :

 \sf \: 1) \:  \sqrt{72}  +   \sqrt{48}

 \sf \longrightarrow \:  \sqrt{72} =   \sqrt{2 \times 2 \times  2\times 3 \times 3}

 \sf \longrightarrow \:  \sqrt{72} =   3 \times 2 \sqrt{2}

 \sf \longrightarrow \:  \sqrt{72} =   6 \sqrt{2}

Given 2 = 1.414

 \sf \longrightarrow \:  \sqrt{72} =   6 (1.414) = \boxed{ \sf 8.484}

Now,

 \sf \longrightarrow \:  \sqrt{48} =   \sqrt{2 \times 2 \times  2\times 2\times 3}

 \sf \longrightarrow \:  \sqrt{48} =   2 \times 2\sqrt{3}

 \sf \longrightarrow \:  \sqrt{48} =   4\sqrt{3}

Given 3 = 1.732

 \sf \longrightarrow \:  \sqrt{48} =   4(1.732)  =  \boxed{ \sf6.928}

Now, 72 + 48

 \sf \longrightarrow \:  \sqrt{72}  +   \sqrt{48}

 \sf \longrightarrow \:  8.484 + 6.928

 \sf \longrightarrow  \large\boxed{ \purple{ \sf \: 15.412}}

________________________________

 \sf \: 2) \:    \: \sqrt{ \dfrac{125}{64} }

 \sf \longrightarrow \:  \sqrt{125} =   \sqrt{5 \times 5 \times5 }

 \sf \longrightarrow \:  \sqrt{125} =   5 \sqrt{5}

Given 5 = 2.236

 \sf \longrightarrow \:  \sqrt{125} =   5 (2.236) =  \boxed{ \sf \: 11.18}

Now,

 \sf \longrightarrow \:  \sqrt{64} =   \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2  }

 \sf \longrightarrow \:  \sqrt{64} =   2 \times 2 \times 2

 \sf \longrightarrow \:  \sqrt{64} =    \boxed{ \sf \: 8}

Now, 125/64 :

 \sf  \longrightarrow \:    \: \sqrt{ \dfrac{125}{64} }

 \sf  \longrightarrow   \cancel\dfrac{11.18}{8}

 \sf \longrightarrow  \large\boxed{ \purple{ \sf \:1.3975}}

Hence,

 \sf \dag \:  \:  \sqrt{72}  +   \sqrt{48}  = 15.412

 \dag \sf \:  \sqrt{ \dfrac{125}{64} }  = 1.3975

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