please answer the above question. as fast as possible tomorrow is exam please
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At first the temperature of the tea was 80℃
After 5 min it came to 50℃
therefore, temp. decreased in 5min is=(80℃-50℃)=30℃.
therefore, temperature decreased in 1min=30℃/5min =6℃/min.
Now, Acc.to question.
temperature decreased from 60℃ to 30℃, is 30℃ .
time taken to decrease from 60 to 30 = 5min
as 6℃ decrease in per minute
therefore, 30℃ decrease in 5min.
plz mark it as brainliest answer.☺☺☺
After 5 min it came to 50℃
therefore, temp. decreased in 5min is=(80℃-50℃)=30℃.
therefore, temperature decreased in 1min=30℃/5min =6℃/min.
Now, Acc.to question.
temperature decreased from 60℃ to 30℃, is 30℃ .
time taken to decrease from 60 to 30 = 5min
as 6℃ decrease in per minute
therefore, 30℃ decrease in 5min.
plz mark it as brainliest answer.☺☺☺
devadarshmpillp39ide:
than you
plz mark it as brainliest answer.
ok
their is mark option
bro I couldn't find it
yes me also
sorry for ur problem
sorry
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