please answer the above question fast
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pH is 2 ... concentration is of [H+] is 10^-2
now it is diluted to 10times of its intial volume
therefore concentration becoms 10^-3
taking negetive log of concentration
pH=3
now it is diluted to 10times of its intial volume
therefore concentration becoms 10^-3
taking negetive log of concentration
pH=3
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