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Using law of conservation of momentum
0= 3x10^-3(v1 )+ 1x10^-3 v2
v1=-v2/3
now total k.e 1/2 x 3x 10^-3 (v1) ²+ 1/2 1 x 10^-3(v2)² = 6.4x 10^4
put value of v1 and find v2
0= 3x10^-3(v1 )+ 1x10^-3 v2
v1=-v2/3
now total k.e 1/2 x 3x 10^-3 (v1) ²+ 1/2 1 x 10^-3(v2)² = 6.4x 10^4
put value of v1 and find v2
sonu806:
where is V2 in the ques
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