please answer the above question fast
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For equillibrium
F⩽ 0.2 N , where n is normal reaction
for max value of f
F= 0.2 mg (becoz n = mg) (m is mass of block a)
F = O.2 x 2x 10 (g=10)
F=4 N
but here force is provided by weight of block b)
F = Mg (where M is mass of block b)
4 =M x 10
M=0.4 kg
hope thats the right ans
F⩽ 0.2 N , where n is normal reaction
for max value of f
F= 0.2 mg (becoz n = mg) (m is mass of block a)
F = O.2 x 2x 10 (g=10)
F=4 N
but here force is provided by weight of block b)
F = Mg (where M is mass of block b)
4 =M x 10
M=0.4 kg
hope thats the right ans
sonu806:
U r correct
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