Question

please answer the above question fast

Answer 1

let coff. for friction be β

F = ma

a =f/m


here force is give by weight of block m1 but it is also opposed by friction

so ... F = m1g - β m2g - β m3 g

F =mg (1-2β)

and total mass is 3m..

therefore


a = mg(1-2β)/3m

a= g(1-2β)/3

i hope that the right ans