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Carbon with atomic no. 6 has electronic configuration [He]2s22p2.
It utilizes three of these electrons to form bond with hydrogen in option 2 positive charge shows one electron is lost so p orbital is vacant.
Similarly, in option 3 two with hydrogen and two free hence vacant p obital..
Hope it helps....
Please mark it brainliest
It utilizes three of these electrons to form bond with hydrogen in option 2 positive charge shows one electron is lost so p orbital is vacant.
Similarly, in option 3 two with hydrogen and two free hence vacant p obital..
Hope it helps....
Please mark it brainliest
Heta11:
Thanks sonu for marking my answer as brainliest
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